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Sheet tension. Is this correct?

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Created by sirgallivant > 9 months ago, 10 Sep 2015
sirgallivant
NSW, 1531 posts
10 Sep 2015 6:12PM
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Multiply sail area in sq. feet by wind speed in knots squared, dividing the result by 232.
Ex: 150 sq feet x 15 knot2 (225) : 232=145 pounds

Yara
NSW, 1322 posts
10 Sep 2015 9:39PM
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It is really a lot more complicated than that. You could tie yourself in theoretical knots, but why not get practical. Hook a simple spring balance onto the end of the sheet and measure the tension. Note the wind speed. The force on the sheet will vary with the square of the wind speed. EG double the wind speed and the force will increase by 4.
The force is proportional to the area, so double the sail area and you will have double force.

All approximations, of course, but better than trying to do pure theory.

rumblefish
TAS, 824 posts
11 Sep 2015 8:17AM
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I have always used this formula
Genoa
www.harken.com.au/content.aspx?id=9096
Main
www.harken.com.au/content.aspx?id=9094

Traveller load is usually 0.2 of mainsheet load



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"Sheet tension. Is this correct?" started by sirgallivant